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4 April, 14:15

What mass of helium, in grams, is required to fill a 6.1-l balloon to a pressure of 1.1 atm at 25 °c?

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  1. 4 April, 14:31
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    PV=nRT

    (1.1) (6.1) = (n) (0.08201) (298)

    6.71=n (0.08201*298)

    n=0.2745613769 moles Helium

    n (Mm) = mass

    0.2745613769 (4.00)

    1.098245508 grams of Helium
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