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28 August, 03:51

Be sure to answer all parts. The combustion of a 40.0-g gaseous mixture of H2 and CH4 releases 3766 kJ of heat. Calculate the amount of each gas in grams. Assume that the product of the combustion of H2 is H2O (l) and that the products of the combustion of CH4 are CO2 (g) and H2O (l).

H2 =

CH4=

+3
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  1. 28 August, 04:10
    0
    Answer:H2=11.4g

    CH4=28.6g

    Explanation:The complete combustion of the two gases can be represented by a balanced reaction below

    1. CH4 + 2O2___CO2+2H2O

    2.2H2+O2___2H2O

    Combining the two we have CH4 + 2H2+3O2___

    CO2+4H2O

    Since the mixture contains 40gof CH4 and 2, therefore 20g of CH4 and 8g of H2 combines.

    Calculated from their molecular Mass i. e CH4 12+4*2) = 20 and 2H2 = 2*2*2=8g

    Mass of CH4=20/28*40=28.6g

    2H2=8/28*40=11.4g
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