Provided that the molar mass of a compound is 543.52 g/mol, how many mg do you need to add to 17 mL of solvent to yield a solution molarity of 3 M?

N. B. M = (mol/L)

Select one:

a. 10.66

b. 27719520.00

c. 27.72

d. 27719.52

e. 3079946.67

27719.52 mg

Explanation:

From the question, we have;

Volume as 17 ml or 0.017 L Molarity as 3 M Molar mass of a compound as 543.52 g/mol

Required to determine the mass of the compound needed to make the solution.

We know that;

Molarity = Moles : Volume

Therefore;

Moles = Molarity * Volume

Hence;

Moles of the compound = 3 M * 0.017 L

= 0.051 Moles

But;

Mass = Moles * Molar mass

= 0.051 moles * 543.52 g/mol

= 27.71952 g

But, 1 g = 1000 mg

Therefore;

Mass (in mg) = 27719.52 mg