Write a balanced equation for the neutralization of potassium hydroxide by phosphoric acid. Use the smallest possible integer coefficients.

Using the smallest coefficient the chemical equation is written as

3KOH (aq) + H3PO4 (aq) → K3PO4 (aq) + 3H2O (aq)

Explanation:

Neutralization reaction is a reaction in which acid and base reacts quantitatively to form salt and water.

Base = potassium hydroxide

acid = phosphoric acid.

KOH = potassium hydroxide

H3PO4 = Phosphoric acid

KOH (aq) + H3PO4 (aq) → K3PO4 (aq) + H2O (aq)

The number of atoms on both side (reactant and product) of the equation are not equal so, we need to balance it.

3KOH (aq) + H3PO4 (aq) → K3PO4 (aq) + 3H2O (aq)

The product are salt and water.

Salt = K3PO4

water = H2O

The equation is balanced on both sides.

The potassium atom is 3 on both sides, oxygen atom is 7 on both sides, hydrogen atom is 6 on both sides and phosphorus atom is 1 on both sides.