How many moles of H2SO4 are there in 0.035L of a 0.500 solution?

I am assuming you forgot to include the unit of molarity, M, at the end of 0.500.

Molarity's formula is M=moles solute/liters solution.

We are given molarity and liters so we can rearrange the equation to solve for moles solute. Therefore:

moles solute=molarity * liters solution

moles solute = 0.500M * 0.035L = 0.0175

Thus there are 0.0175 mols of H2SO4 in 0.035L of a 0.500M solution.