Magnesium is obtained from sea water. Ca (OH) 2 is added to sea water to precipitate Mg (OH) 2. The precipitate is filtered and reacted with HCl to produce MgCl2. The MgCl2 is electrolyzed to produce Mg and Cl2. If 185 g of magnesium are recovered from 962 g of MgCl2, what is the percent yield for this reaction? Answer in units of percent

Question

Elvis Hancock

Chemistry

27 October, 01:44

Magnesium is obtained from sea water. Ca (OH) 2 is added to sea water to precipitate Mg (OH) 2. The precipitate is filtered and reacted with HCl to produce MgCl2. The MgCl2 is electrolyzed to produce Mg and Cl2. If 185 g of magnesium are recovered from 962 g of MgCl2, what is the percent yield for this reaction? Answer in units of percent

+1

Answers (1)

Know the Answer?

Brenda Bond · Answer 1

Answer is: the percent yield for this reaction is 75,37%.

m (MgCl₂) = 962 g.

n (MgCl₂) = m (MgCl₂) : M (MgCl₂).

n (MgCl₂) = 962 g : 95,21 g/mol.

m (MgCl₂) = 10,1 mol.

n (MgCl₂) : n (Mg) = 1 : 1.

n (Mg) = 10,1 mol.

m (Mg) = 10,1 mol · 24,3 g/mol.

m (Mg) = 245,43 g.

ω (Mg) = 185 g : 245,43 g · 100% = 75,37%.