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27 September, 01:55

The reaction N2 + 3 H2 → 2 NH3 is used to produce ammonia. When 450. g of hydrogen was reacted with nitrogen, 1575 g of ammonia were produced. What is the percent yield of this reaction?

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  1. 27 September, 02:11
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    The percent yield of this reaction is 70%

    Explanation:

    The reaction is: N₂ + 3H₂ → 2NH₃

    We only have the mass of H₂, so we assume that N₂ is in excess

    We convert the mass to moles, to work with the reaction:

    450 g. 1mol / 2 g = 225 moles

    Ratio is 2:3. 3 moles of H₂ can produce 2 moles of ammonia

    Therefore 225 moles of H₂ will produce (225.2) / 3 = 150 moles

    This is the 100% yield reaction → We convert the moles of NH₃ to mass

    150 mol. 17g / 1mol = 2550 g

    Percent yield = (Produced yield/Theoretical yield).100

    Percent yield = (1575g/2550g). 100 = 70%
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