At what temperature in K will 4.00 moles of gas occupy a volume of 12.0 L at a pressure of 5.60 atm?

The answer to your question is T = 204.9°K

Explanation:

Data

Temperature = T = ?

number of moles = n = 4

Volume = V = 12 L

Pressure = P = 5.60 atm

constant of gases = 0.082 atm L / mol °K

Process

To solve this problem, use the Ideal Gas Law and solve it for T

Formula

PV = nRT

T = PV / nR

-Substitution

T = (5.60) (12) / (4) ((0.082)

-Simplification

T = 67.2 / 0.328

-Result

T = 204.9°K

Temperature is 204.9° K

Explanation:

For ideal gas,

PV = nRT

where, p is the pressure = 5.60 atm

V is the volume = 12.0L

n is the number of moles = 4.00 moles

R is the gas constant = 0.08206 L atm mol⁻¹ k⁻¹

T is the temperature = ?

T = PV/nR

substituting the values into the equation

= (5.60*12.0) / (4.00*0.082)

= 204.878° K

= 204.9° K