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22 July, 08:17

Calculate the work done in joules when 1.0 mole of water vaporizes at 1.0 atm and 100°C. Assume that the volume of liquid water is negligible compared with that of steam at 100°C and ideal gas behavior.

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  1. 22 July, 08:39
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    The amount of work done W = - 30.6 J

    Explanation:

    Pressure = 1 atm

    n = 1 mole

    T = 100 °c = 373 K

    From ideal gas equation

    P V = n R T

    Put all the values in above equation we get

    1 * V = 1 * 0.08206 * 373

    V = 30.6 L

    Work done is calculated by

    W = - P ΔV

    W = - 1 * 30.6

    W = - 30.6 J

    Therefore the amount of work done W = - 30.6 J
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