Ask Question
27 September, 07:35

For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = - 20.5 kJ/mol?

+4
Answers (1)
  1. 27 September, 07:44
    0
    Q = 245 = 2.5 * 10^2

    Explanation:

    ΔG = ΔGº + RTLnQ, so also ΔGº = - RTLnK

    R = 8,314 J/molK, T=298K

    ΔGº = - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

    ΔG = ΔGº + RTLnQ → - 20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol * LnQ

    → 5.5 = LnQ → Q = 245 = 2.5 * 10^2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = - 20.5 kJ/mol? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers