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15 August, 10:38

How many milliliters of 50 by mass hno3 solution, with a density of 2.00 grams per milliliter are required to make 500 ml

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  1. 15 August, 11:07
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    V = 331.13 mL of 50 by mass NO3 solution

    Explanation:

    ∴ δ sln = 2.00 g/mL

    ∴ %m HNO3 = 50% = (mass HNO3 / mass sln) * 100

    ∴ V required sln = 500 mL

    ∴ δ HNO3 = 1.51 g/mL ... from literature

    ⇒ V sln = mass sln / δ sln = 500 mL

    ⇒ mass sln = (500 mL) * (2 g/mL) = 1000 g sln

    ⇒ mass HNO3 = (0.5) * (1000 g) = 500 g HNO3

    ⇒ V HNO3 = (500 g HNO3) * (ml HNO3/1.51 g) = 331.13 mL
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