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6 March, 05:55

When 15.0 mL of a 6.42*10-4 M sodium sulfide solution is combined with 25.0 mL of a 2.39*10-4 M manganese (II) acetate solution does a precipitate form? (yes or no) For these conditions the Reaction Quotient, Q, is equal to.

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  1. 6 March, 06:22
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    Q = 3.59x10⁻⁸

    Yes, precipitate is formed.

    Explanation:

    The reaction of Na₂S with Mn (CH₃COO) ₂ is:

    Na₂S (aq) + Mn (CH₃COO) ₂ (aq) ⇄ MnS (s) + 2 Na (CH₃COO) (aq).

    The solubility product of the precipitate produced, MnS, is:

    MnS (s) ⇄ Mn²⁺ (aq) + S²⁻ (aq)

    And Ksp is:

    Ksp = 1x10⁻¹¹ = [Mn²⁺] [S²⁻]

    Molar concentration of both ions is:

    [Mn²⁺] = 0.015Lₓ (6.42x10⁻⁴mol / L) / (0.015 + 0.025) L = 2.41x10⁻⁴M

    [S²⁻] = 0.025Lₓ (2.39x10⁻⁴mol / L) / (0.015 + 0.025) L = 1.49x10⁻⁴M

    Reaction quotient under these concentrations is:

    Q = [2.41x10⁻⁴M] [1.49x10⁻⁴M]

    Q = 3.59x10⁻⁸

    As Q > Ksp, the equilibrium will shift to the left producing MnS (s) the precipitate
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