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9 November, 21:51

4. 213.4 grams of NaNO3 contain how many moles?

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  1. 9 November, 22:12
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    mass of NaNO3 = 213.4g

    Molar mass = {23 + 14 + 3 (16) }

    = 23 + 14 + 48

    = 85g/mol

    Amount = mass/molar mass

    = 213.4/85

    = 2.5moles of NaNO3
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