Which reaction below represents the first ionization of sb? which reaction below represents the first ionization of? sb2 - (g) → sb3 - (g) + e-sb + (g) + e - → sb2 + (g) sb (g) + e - → sb - (g) sb - (g) + e - → sb2 - (g) sb (g) → sb + (g) + e-?

Question

Journey Foster

Chemistry

10 November, 09:47

Which reaction below represents the first ionization of sb? which reaction below represents the first ionization of? sb2 - (g) → sb3 - (g) + e-sb + (g) + e - → sb2 + (g) sb (g) + e - → sb - (g) sb - (g) + e - → sb2 - (g) sb (g) → sb + (g) + e-?

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Answers (1)

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Jairo Smith · Answer 1

Answer is: Sb (g) → Sb⁺ (g) + e⁻.

Neutral atom in gas state lose one valence electron and become cation with postive charge.

The first ionisation energy is the energy required to remove one mole of the valence electrons from one mole of gaseous atoms to produce one mole of gaseous ions each with a charge of 1+.

Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.