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29 February, 09:53

What was the total number of calories lost when 10 grams of water at 80c is cooled to 60c?

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  1. 29 February, 10:08
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    Q = - 200 cal

    Explanation:

    Given dа ta:

    Calories lost = ?

    Mass of water = 10 g

    Initial temperature = 80°C

    Final temperature = 60°C

    Solution:

    Specific heat capacity of water is 1 cal/g.°C

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = T2 - T1

    ΔT = 60°C - 80°C

    ΔT = - 20°C

    Q = m. c. ΔT

    Q = 10 g. 1 cal/g.°C. - 20°C

    Q = - 200 cal
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