At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. at this temperature, 0.500 mol of h2 and 0.500 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?

equation: h2 + i2 = 2hi

Question

Paisley Mccall

Chemistry

5 October, 21:07

At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. at this temperature, 0.500 mol of h2 and 0.500 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?

equation: h2 + i2 = 2hi

+4

Answers (1)

Know the Answer?

Ean Vaughan · Answer 1

When the balanced equation for the reaction is:

H2 (g) + i2 (g) ⇄ 2Hi

initial 0.5 0.5 X

-X - X + X

Final (0.5-x) (0.5-x) 2X

by substitution at the Kc formula:

Kc = [Hi]^2 / [H2] * [i2]

53.3 = (2X) ^2 / (0.5-X) (0.5-X) by taking the square route

√53.3 = 2X / (0.5-X)

∴X = 0.39 m

∴[Hi] = 0.39 m

At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. at this temperature, 0.500 mol of h2 and 0.500 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?equation: h2 + i2 = 2hi

At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. at this temperature, 0.500 mol of h2 and 0.500 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?

equation: h2 + i2 = 2hi