A 10.0 ml solution of 0.300 m nh3 is titrated with a 0.100 m hcl solution. calculate the ph after the addition of 10.0 ml hcl.

Question

Sullivan Callahan

Chemistry

27 May, 22:24

A 10.0 ml solution of 0.300 m nh3 is titrated with a 0.100 m hcl solution. calculate the ph after the addition of 10.0 ml hcl.

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Big Foot · Answer 1

Answer;

pH = 9.55

Explanation;

[NH3] = 2.0 mmol/20.0 mL = 0.100 M

[NH4+] = 1.00 mmol/20.0 mL = 0.0500 M

Ka = (1.0 * 10^-14) / (1.8 * 10^-5)

= 5.56 * 10^-10

pKa = log Ka = 9.25

pH = pKa + log ([base]/[acid])

= 9.25 + log (0.100/0.0500)

= 9.55