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29 September, 09:56

A sample of neon gas occupies a volume of 2.8 L at 1.8 atm. What would it's volume be at 1.2 atm?

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  1. 29 September, 09:58
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    Answer: V = 4.2L

    Explanation: To solve for the new volume we use Boyle's Law.

    P1V1 = P2V2

    Derive for V2 the new volume.

    V2 = P1V1 / P2

    V2 = 1.8 atm x 2.8 L / 1.2 atm

    = 4.2 L
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