A certain hydrocarbon had the molecular formula C16H26 and contained two triple bonds. Ozonolysis gave CH3 (CH2) 4CO2H and HO2CCH2CH2CO2H as the only products. Draw a reasonable structure for this hydrocarbon. Click the draw structure" button to launch the drawing utility."

Question

Marshmallow

Chemistry

9 March, 19:31

A certain hydrocarbon had the molecular formula C16H26 and contained two triple bonds. Ozonolysis gave CH3 (CH2) 4CO2H and HO2CCH2CH2CO2H as the only products. Draw a reasonable structure for this hydrocarbon. Click the draw structure" button to launch the drawing utility."

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Axel Cervantes · Answer 1

the compound is hexadeca-6,10-diyne.

Explanation:

As given that the compound has two triple bonds and it is giving carboxylic acids on ozonolyis so this is an oxidative ozonolysis.

We are getting only two kinds of products, it means the triple bonds are located at symmetrical position.

The middle carbon chain must have four carbons and the side chains must have six carbons each,

The structure of hydrocarbon is shown in figure.