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9 December, 11:03

What volume of a 0.750 M solution of hydrochloric acid a solution of HCL can be prepared from the HCL produced by the reaction of 25.0 of NaCl with an excess of sulphuric acid?

NaCl + H2SO4? HCl + NaHSO4

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Answers (1)
  1. 9 December, 11:29
    0
    0.570 L

    Explanation:

    Given:

    Concentration of the HCl solution = 0.750 M

    Mass of NaCl in the reaction = 25.0

    Number of moles of NaCl in the reaction = Mass of NaCl / Molar mass of NaCl

    also,

    Molar mass of NaCl = 22.98 + 35.45 = 58.43 grams

    thus,

    Number of moles of NaCl in the reaction = 25 / 58.43 = 0.4278 moles

    now,

    1 mol of NaCl reacts to form 1 mol of HCl

    thus,

    0.4278 moles of NaCl reacts to form 0.4278 mol of HCl

    also,

    Concentration = Moles / volume of solution

    0.750 = 0.4278 / volume of solution

    or

    volume of solution = 0.570 L
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