77.60 ml of. 210 M NaOH are required to neutralize 25.05 ml

ofH2SO4 solution in a titrationexperiment.

Calculate the molarity and normality of

theH2SO4 solution.

Molarity = 0.650 M

Normality = 1.30 N

Explanation:

In case of titration, the following formula can be used -

M₁V₁ = M₂V₂

where,

M₁ = concentration of acid,

V₁ = volume of acid,

M₂ = concentration of base,

V₂ = volume of base.

from, the question,

M₁ = ? M

V₁ = 25.05mL

M₂ = 0.210 M

V₂ = 77.60 mL

Using the above formula, the molarity of acid, can be calculated as,

M₁V₁ = M₂V₂

M₁ * 25.05mL = 0.210 M * 77.60 mL

M₁ = 0.650 M

Hence, the molarity of the acid = 0.650 M

Normality of a diprotic acid can be calculated by multiplying 2 with the value of molarity,

Hence,

Normality = M * 2 = 0.650 * 2 = 1.30 N