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16 July, 21:09

The correct mathematical expression for finding the molar solubility (s) of calcium phosphate is

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  1. 16 July, 21:24
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    Answer is: The molar solubility of calcium phosphate is 108s⁵ = Ksp.

    Balanced chemical reaction: Ca ₃ (PO₄) ₂ (s) → 3Ca²⁺ (aq) + 2PO₄³⁻ (aq).

    [Ca² ⁺] = 3s (Ca₃ (PO₄) ₂) = 3s.

    [PO ₄³⁻] = 2s.

    Ksp = [Ca² ⁺]³ · [PO₄³⁻]².

    Ksp = (3s) ³ · (2s) ².

    Ksp = 108s ⁵.

    s = ⁵√ (Ksp : 108).
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