How many representative particles are in a 53.79 gram sample of SrCO3?

To find the number of particles, you need to use Avogadro's number

6.02 x 10^23 = 1 mol

As you can see, before we can convert to particles, we need moles. So let's first convert grams to moles using the molar mass (molecular weight) of the compound

molar mass of SrCO₃ = 87.6 + 12.0 + (3 x 16.0) = 147.6 g/mol

53.79 g (1 mol / 147.6 g) = 0.364 mol

now let's convert moles to particles using Avogadro's number

0.364 mol SrCO₃ (6.02x10^23 / 1 mol) = 2.19 x 10^23

Remember representative particles / molecules / atoms are all the same

convert from grams - > moles

hope this clears thing