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8 December, 23:15

How many milliliters of 12.0 m hcl (aq) are needed to prepare 905.0 ml of 1.00 m hcl (aq) ?

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  1. 8 December, 23:45
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    The ml of 12.0 M HCL needed to prepare 905.0 ml of 1.00m hcl is calculated using M1V1 = M2V2 formula

    M1 = 12.0 M

    V1=?

    M2 = 905.0 ml

    V2 = 1.00M

    V1 is therefore = M2V2/M1

    =905 x 1.00/12.0 = 75.42 ml
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