Calculate the concentration of all ions present in each of the following solutions of strong electrolytes. a. 0.100 mole of Ca (NO3) 2 in 100.0 mL of solution

[Ca²⁺] = 1M

[NO₃⁻] = 2M

Explanation:

Calcium nitrate dissociates in water as follows:

Ca (NO₃) ₂ ⇒ Ca²⁺ + 2NO₃⁻

The moles of Ca²⁺ can be found using the molar relationship between Ca (NO₃) ₂ and Ca²⁺

(0.100mol Ca (NO₃) ₂) (Ca²⁺ / Ca (NO₃) ₂) = 0.100 mol Ca²⁺

The concentration of Ca²⁺ is then:

[Ca²⁺] = n/V = (0.100mol) / (100.0mL) x (1000ml) / (1L) = 1M

Similarly, moles of NO₃⁻ can be found using the molar relationship between Ca (NO₃) ₂ and NO₃⁻:

(0.100mol Ca (NO₃) ₂) (2NO₃⁻/Ca (NO₃) ₂) = 0.200 mol NO₃⁻

The concentration of NO₃⁻ is then:

[NO₃⁻] = (0.200mol) / (100.0mL) x (1000ml) / (1L) = 2M