What is the number of sulfur atoms that equal a mass of 32.07 amu?

As we know that mole of Sulfur is related to Number of Atoms and Mass as follow,

1 Mole = 6.022 * 10²³ Atoms

1 Mole = 32.07 g

It means 1 Mole of Sulfur contain 6.022 * 10²³ Atoms and weights 32.07 g.

Result:

32.07 g of Sulfur contains 6.022 * 10²³ Atoms.