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12 April, 23:42

A student reduces the temperature from a 300 cm3 balloon from 60°C to 20°C. What will the new volume of the balloon be?

264 cm3

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  1. 13 April, 00:09
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    To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

    T1 / V1 = T2 / V2

    V2 = T2 x V1 / T1

    V2 = 293.15 x 300 / 333.15

    V2 = 263.98 cm^3
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