Household bleach is an aqueous solution of sodium hypochlorite (NaClO). For a kinetics experiment, 4 mL of a 5% (w/w) bleach solution was diluted in a 100 mL volumetric flask. 6 mL of this diluted solution is added to 6 mL of dye in a reaction vessel. What is the concentration of bleach (in M) in the reaction vessel? Assume the density of the bleach solution is 1.11 g/mL.

Question

Zaria Scott

Chemistry

20 January, 04:57

Household bleach is an aqueous solution of sodium hypochlorite (NaClO). For a kinetics experiment, 4 mL of a 5% (w/w) bleach solution was diluted in a 100 mL volumetric flask. 6 mL of this diluted solution is added to 6 mL of dye in a reaction vessel. What is the concentration of bleach (in M) in the reaction vessel? Assume the density of the bleach solution is 1.11 g/mL.

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Alfredo Duffy · Answer 1

Given Mass of 4mL of bleach solution = 4mL x 1.11 g/mL = 4.44g Mass of NaClO in 4.44g beach solution = 0.05 x 100 / 4.44g = 1.126g Moles of NaClO = mass / molar mass molar mass of NaClO = 74.44g/mol moles = 1.126g/74.44g/mol = 0.0151moles

Now when 6mL of this solution is taken, moles of NaClO in this 6mL;

= 6mL x 0.0151moles / 100mL = 0.000906moles

This is added to 6mL dye. Therefore, total volume of solution = 12mL total volume = 0.012L hence, concentration of bleach (in M) in the reaction vessel; number of moles/volume = 0.000906moles/0.012L = 0.0755M