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25 January, 19:03

Analysis of a compound indicates that it contians 1.04 g K, 0.70 g Cr, and 0.86 g O. Find its empirical formula.

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  1. 25 January, 19:05
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    K2CrO4

    Explanation:

    To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:

    K = 1.04/39.0983 = 0.027

    Cr = 0.70/51.9961 = 0.013

    O = 0.86/15.999 = 0.054

    We now divide by the smallest which is the number of moles of the Chromium

    K = 0.027/0.013 = 2

    Cr = 0.013/0.013 = 1

    K = 0.054/0.013 = 4 approximately

    The empirical formula is thus:

    K2CrO4
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