Given the mass lost during the reaction when the alka seltzer is the limiting reagent and that the molar mass of carbon dioxide is 44.01 g/mol, how many moles of CO2 were produced

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Jack Ibarra

Chemistry

16 June, 20:58

Given the mass lost during the reaction when the alka seltzer is the limiting reagent and that the molar mass of carbon dioxide is 44.01 g/mol, how many moles of CO2 were produced

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Ismael Byrd · Answer 1

Alka-seltzer is an effervescent antacid which neutralizes the acid of the stomach by generating CO2. The chemical formula of alka-seltzer is C16H17NaO14. In this case, if we are given the mass of the antacid used, then by stoichiometry, mass alka-seltzer * (1 / molar mass of alk-selz) * (1 mol Co2 / 1 mol alk-seltz) * (44 g/molCo2). That is how you get the mass of Co2 produced.