A student took 100 ml of a solution of mg (oh) 2 and reacted it with h2so4 (aq) to calculate the concentration of hydroxide ions in the solution. if 13.75 ml of 0.010 m h2so4 was used to react with all of the oh - (aq) in the 100-ml solution, what was the concentration of hydroxide ions dissolved in the 100-ml solution

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Russo

Chemistry

26 June, 08:58

A student took 100 ml of a solution of mg (oh) 2 and reacted it with h2so4 (aq) to calculate the concentration of hydroxide ions in the solution. if 13.75 ml of 0.010 m h2so4 was used to react with all of the oh - (aq) in the 100-ml solution, what was the concentration of hydroxide ions dissolved in the 100-ml solution

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Yadiel Flynn · Answer 1

Mg (OH) ₂ + H₂SO₄ → MgSO₄ + 2H₂O

c (OH⁻) - ?

v₁=100 mL

c₂=0.010 mmol/mL

v₂=13.75 mL

Mg (OH) ₂ → Mg²⁺ + 2OH⁻

c (OH⁻) = 2c₁

n{Mg (OH) ₂}=n{H₂SO₄}

n{Mg (OH) ₂}=c₁v₁=c (OH⁻) v₁/2

n{H₂SO₄}=c₂v₂

c (OH⁻) v₁/2=c₂v₂

c (OH⁻) = 2c₂v₂/v₁

c (OH⁻) = 2*0.010*13.75/100=0.00275 mmol/mL = 2.75*10⁻³ mol/L

2.75*10⁻³ mol/L