If you want to prepare 0.50 liters of a 0.35 M solution of NaNO3, how many grams of the salt should

you weigh out?

14.87 g

Explanation: Molarity refers to the concentration of a solution in moles per liter. It is calculated by dividing the number of moles of solute and the volume of the solution.

We are given;

Volume as 0.5 liters

Molarity as 0.35 M

We are required to calculate the mass of the solute NaNO₃

Step 1 : Find the number of moles of the solute NaNO₃

Moles = Molarity * Volume

Moles = 0.35 M * 0.5 L

= 0.175 moles

Step 2: Mass of the solute NaNO₃

Mass is calculated by multiplying the number of moles by the molar mass of the compound.

Molar mass of NaNO₃ = 84.9947 g/mol

Therefore;

Mass of NaNO₃ = 0.175 moles * 84.9947 g/mol

= 14.874 g

= 14.87 g

Thus, the mass of the salt solute is 14.87 g