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1 October, 15:57

A cylindrical specimen of some metal alloy having an elastic modulus of 126 GPa and an original cross-sectional diameter of 3.4 mm will experience only elastic deformation when a tensile load of 2130 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.45 mm.

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  1. 1 October, 16:21
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    The maximum length of the specimen before deformation is 240.64 mm

    Explanation:

    Strain = stress : elastic modulus

    stress = load : area

    load = 2130 N

    diameter = 3.4 mm = 3.4*10^-3 m

    area = πd^2/4 = 3.142 * (3.4*10^-3) ^2/4 = 9.08038*10^-6 m^2

    stress = 2130 N : 9.08038*10^-6 m^2 = 2.35*10^8 N/m^2

    elastic modulus = 126 GPa = 126*10^9 Pa

    Strain = 2.35*10^8 : 126*10^9 = 0.00187

    Length = extension : strain = 0.45 mm : 0.00187 = 240.64 mm
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