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Jazmine Adkins
Chemistry
1 March, 05:35
How do you determine a limiting or excess reagent
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Arroyo
1 March, 05:45
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Determine the mol ratio of both the reagents
Then calculate the mol for both reagents
eg NaOH + HCl - - > NaCl + H2O
given in qns NaOH is 5g and 50cm^3 of 0.2mol/dm^3 HCL
from eqn:
Mole ratio of NaOH to HCL = 1:1
from calculations:
no. of mole of NaOH = 5 / (23+16 + 1) = 0.125mol (excess)
no. of mole of HCL = 0.2 * 50/1000 = 0.01 mol (limiting)
NaOH : HCL should equals to 1:1 however from calculations it is not 1:1 and n (HCL) < n (NaOH) HCL limiting, NaOH excess
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