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23 July, 02:44

Calculate the mass of CO2 produced by the combustion of a tank of gasoline. Assume the mass of gasoline is 46.0 kg and that gasoline is pure octane (C8H18).

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  1. 23 July, 02:54
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    142035.09g

    Explanation:

    Let us write a balanced equation for the reaction. This is illustrated below:

    2C8H18 + 25O2 - > 16CO2 + 18H2O

    Molar Mass of C8H18 = (8x12) + (18x1) = 96 + 18 = 114g/mol

    Mass of C8H18 from the balanced equation = 2 x 114 = 228g

    Mass of C8H18 from the question = 46kg = 46 x 1000 = 46000g

    Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g

    Mass of CO2 from the balanced equation = 16 x 44 = 704g

    From the equation,

    228g of C8H18 produced 704g of CO2.

    Therefore, 46000g of C8H18 will produce = (46000 x 704) / 228 = 142035.09g of CO2
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