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24 February, 03:13

PH of 6.7X10^-4 of H2SO4

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  1. 24 February, 03:40
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    Assuming 6.7x10^-4 is in units of molarity, simply do - log (M) = pH. Substitute and get - log (6.7x10^-4) and when solving you find 3.17 is the pH
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