A syringe contains 56.05 mL of gas at 315.1 K. What volume will that gas occupy if the temperature is increased to 380.5 K?

a) 12.41

b) 46.42

c) 67.68

d) 81.74

Question

Wade Knight

Chemistry

30 December, 13:22

A syringe contains 56.05 mL of gas at 315.1 K. What volume will that gas occupy if the temperature is increased to 380.5 K?

a) 12.41

b) 46.42

c) 67.68

d) 81.74

+3

Answers (2)

Know the Answer?

Jordan Hensley · Answer 1

This is one of the ideal gas laws. Presumably the pressure remains the same so it is not part of the givens.

Formula

V / T = V1 / T1

Givens

V = 56.05 mL T = 315.1 degrees Kelvin V1 = x T1 = 380.5 degrees Kelvin

Solution

56.05/315.1 = x/380.5 Simplify the left.

0.1779 = x / 380.5 Multiply both sides by 380.5

0.1779 * 380.5 = 380.5x/380.5

67.68 mL = x This is your answer

Arjun Jackson · Answer 2

Answer:67.68

Explanation:

actually the formula is for Charles Law and it is V1/T1 = V2/T2

A syringe contains 56.05 mL of gas at 315.1 K. What volume will that gas occupy if the temperature is increased to 380.5 K?a) 12.41b) 46.42c) 67.68d) 81.74

A syringe contains 56.05 mL of gas at 315.1 K. What volume will that gas occupy if the temperature is increased to 380.5 K?

a) 12.41

b) 46.42

c) 67.68

d) 81.74