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11 November, 19:59

Empirical formula of a compound composed of 32.1 g potassium (k) and 6.57 g oxygen (o) ?

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  1. 11 November, 20:08
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    The empirical formula is K₂O.

    The empirical formula is the simplest whole-number ratio of atoms in a compound.

    The ratio of atoms is the same as the ratio of moles.

    So, our job is to calculate the molar ratio of K to O.

    Step 1. Calculate the moles of each element

    Moles of K = 32.1 g K * (1 mol K / (39.10 g K = ) = 0.8210 mol K

    Moles of O = 6.57 g O * (1 mol O/16.00 g O) = 0.4106 mol 0

    Step 2. Calculate the molar ratio of each element

    Divide each number by the smallest number of moles and round off to an integer

    K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

    Step 3: Write the empirical formula

    EF = K₂O
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