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21 November, 02:09

To double the average kinetic energy of helium

atoms in a balloon at 27 °C, the temperature of the gas must be

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Answers (1)
  1. 21 November, 02:38
    0
    54°C

    Explanation:

    Hello,

    To find the temperature of the gas, we would need a relationship between kinetic energy and temperature.

    K. E = 3/2RT/Na

    Where K. E = kinetic energy

    R = ideal gas constant

    T = temperature of the ideal gas

    Na = Avogadro's number

    2K. E₁ = K. E₂ (required)

    Since both constant (R and Na) are equal,

    K. E = T (direct proportionality)

    But T = 27°C

    T2 = 2 * 27 = 54°C

    To double the kinetic energy of a helium gas at 27°C the temperature of the gas should be increased to 54°C
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