A piece of a newly synthesized material of mass 25.0 g at 80.0◦C is placed in a calorime - ter containing 100.0 g of water at 20.0◦C. If the final temperature of the system is 24.0◦C, what is the specific heat capacity of this material?1. 4.76 J · g-1 · (◦C) - 12. 1.19 J · g-1 · (◦C) - 13. 0.84 J · g-1 · (◦C) - 14. 0.30 J · g-1 · (◦C) - 15. 7.46 J · g-1 · (◦C) - 1

the correct answer is b) c mat = 1.19 J / g°C

Explanation:

if the calorimeter is isolated, all the heat absorbed by water is due to the heat released by the material:

Q water = - Q material

since Q = m * c * (T final - T inicial), m=mass, c = specific heat capacity, T final and T initial = final and initial temperature

denoting w as water, mat as material:

m w * c w * (T final - T i w) = - m mat * c mat * (T final - T i mat) = m mat * c mat * (T i mat - T final)

c mat = m w * c w * (T final - T i w) / [ m mat * (T i mat - T final) ]

replacing values, assuming c water = 4.186 J/g°C

c mat = 100 g * 4.186 J/g°C * (24°C - 20°C) / [ 25 g * (80°C - 24°C) ] = 1.19°J/g°C

therefore the correct answer is b) c mat = 1.19 J / g°C