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18 September, 17:38

2al (s) + 3cl2 (g) →2alcl3 (s) δh∘ = - 1408.4 kj. how much heat (in kilojoules) is released on reaction of 4.70 g of al?

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  1. 18 September, 17:57
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    - 122.58 kJ

    Solution:

    According to following equation,

    2 Al + 3 Cl ₂ → 2 AlCl ₃ δH ° = - 1408.4 kJ

    When,

    54 g (2 mole) Al on reaction releases = 1408.4 kJ heat

    So,

    4.70 g of Al will release = X kJ of Heat

    Solving for X,

    X = (4.70 g * 1408.4 kJ) : 54 g

    X = - 122.58 kJ
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