How many copper will react with 33.9l of nitrogen stp produce copper nitride

Copper reacts with Nitrogen to produce Copper Nitride

6 Cu + N₂ → 2 Cu₃N

At S. T. P

22.4 L (1mole) of N₂ reacts with = 381.24 g of Cu to produce Cu₃N

So,

33.9 L of N₂ will react with = X g of Cu

Solving for X,

X = (33.9 L * 381.24 g) : 22.4 L

X = 576.96 g of Cu

As,

Moles = Mass / M. mass

Moles = 576.96 g / 63.54 g/mol

Moles = 9.08 moles of Cu

Result:

So, 33.9 L of N₂ will react with 576.96 g (9.08 moles) of Cu.