An antifreeze solution is made by mixing ethylene glycol (ρ = 1116 kg/m3) with water. suppose the specific gravity of such a solution is 1.05. assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution.

Question

Ariel Ellis

Chemistry

2 July, 13:13

An antifreeze solution is made by mixing ethylene glycol (ρ = 1116 kg/m3) with water. suppose the specific gravity of such a solution is 1.05. assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution.

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Dean Jefferson · Answer 1

Answer is: the volume percentage of ethylene glycol in the solution is 43.1%.

V (solution) = 1 m ³.

d (solution) = 1050 kg/m³.

m (solution) = 1050 kg.

d (ethylene glycol) = 1116 kg/m³.

d (water) = 1000 kg/m³.

m (solution) = d (ethylene glycol) · V (ethylene glycol) + d (water) · V (water).

V (ethylene glycol) = 1m³ - V (water).

1050 kg = 1116 kg/m³ · (1m³ - V (water)) + 1000 kg/m³ · V (water).

1050 kg = 1116 kg - 1116·V (water) + 1000·V (water).

116 kg/m³ ·V (water) = 66kg.

V (water) = 0.569 m³.

V (ethylene glycol) = 1 m³ - 0.569 m³ = 0.431 m³.

percentage = 0.431 m³ : 1 m³ · 100% = 43.1%.