Suppose two students need to prepare three solutions, each one-half as concentrated as the previous, from a stock solution. (a) One student dilutes 10 mL stock solution to a final volume of 20 mL. S/he dilutes 10 mL stock solution to a final volume of 40 mL. S/he dilutes 10 mL stock solution to a final volume of 60 mL. Does s/he have the solutions at the concentrations desired

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Chemistry

25 October, 22:07

Suppose two students need to prepare three solutions, each one-half as concentrated as the previous, from a stock solution. (a) One student dilutes 10 mL stock solution to a final volume of 20 mL. S/he dilutes 10 mL stock solution to a final volume of 40 mL. S/he dilutes 10 mL stock solution to a final volume of 60 mL. Does s/he have the solutions at the concentrations desired

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Adrian · Answer 1

When a solution is diluted, its strength is decreased according to following

formula

S₁V₁ = S₂V₂

So when volume is doubled, strength becomes half. One student dilutes 10 mL stock solution to a final volume of 20 mL. Its strength becomes half.

When S/he dilutes 10 mL stock solution to a final volume of 60 mL.,

strength becomes 1/6 times.

So the first two experiment gives three solution each one-half as concentrated as the previous.