What is the concentration (M) of CH3OH in a solution prepared by dissolving 12.5 g of CH3OH in sufficient water to give exactly 230 mL of solution?

1.7 M

Explanation:

Concentration is the number of moles of solute dissolved in 1 L of solution

Concentration = number of moles of solute / volume of solution

Number of moles of solute needs to be calculated first

Mass of methanol - 12.5 g

Molar mass of methanol - 32 g/mol

Number of methanol moles - 12.5 g / 32 g/mol = 0.39 mol

Therefore concentration is = 0.39 mol / 0.230 L = 1.7 mol/L

Concentration is 1.7 M