Determine the standard cell potential (Ecell0) and balanced equation for the voltaic cell:
MnO4 - (aq) + I - (aq) → I2 (aq) + Mn2 + (aq)
where:
MnO4-+5H + (aq) + 5e+→ Mn2 + (aq) + 4H2O (l) : Ered0 = + 1.51V.
I2 (s) + 2e-→2I - (aq) : Ered0 = + 0.54 V.
A) 16H + (aq) + 2MnO4 - (aq) + 10I - (aq) →5I2 (aq) + 2Mn2 + (aq) + 8H2O (l):
Ecell0 = - 0.97 V.
B) 16H + (aq) + 2MnO4 - (aq) + 10I - (aq) →5I2 (aq) + 2Mn2 + (aq) + 8H2O (l):
Ecell0 = - 2.05 V.
C) 16H + (aq) + 2MnO4 - (aq) + 10I - (aq) →5I2 (aq) + 2Mn2 + (aq) + 8H2O (l):
Ecell0 = + 0.97 V.
D) 8H + (aq) + 2MnO4 - (aq) + 10I - (aq) →5I2 (aq) + 2Mn2 + (aq) + 8H2O (l):
Ecell0 = + 0.97 V.
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