Ignoring lone-pair effects, what is the smallest bond angle in clf5?

ClF5 contains 42 electrons. Ten of them are bonded pair of electrons. Thirty are in lone pairs with F atoms. So accounting for 40 electrons. The remaining two electrons are left on Cl as a lone pair. So, the bond angles will be more or less equal to 90 degrees due to the extra repulsion from the delocalized lone pair.