Ask Question
26 February, 06:25

A 0.167-g sample of an unknown compound contains 0.00278 mol of the compound. Elemental analysis of the acid gives the following percentages by mass: 40.00% C; 6.71% H; 53.29% O.

+2
Answers (1)
  1. 26 February, 06:43
    0
    Emperical formula of the acid is CH2O

    Molecular formula is C2H4O2

    Explanation:

    C. H. O

    % by mass. 40. 6.71 53.29

    MW. 12. 1. 16

    Mole 40/12. 6.71/1. 53.29/16

    3.33. 6.71. 3.33

    3.33/3.33 6.71/3.33 3.33/3.33

    1. 2. 1

    Emperical Formula (EF) : CH2O

    Molecular Formula (MF)

    Molecular Weight (MW) of acid = mole/mass = 0.00278/0.167 = 60g/mol

    MF = (EF) n = 60

    (CH2O) n = 60

    (12+2+16) n = 60

    30n = 60

    n = 60/30 = 2

    Molecular formula = (EF) n = (CH2O) 2 = C2H4O2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 0.167-g sample of an unknown compound contains 0.00278 mol of the compound. Elemental analysis of the acid gives the following ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers