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23 February, 02:44

A sample of air with a volume of 2.20m3 at a pressure of 105 KPa and a temperature of 30c is cooled to 10c and the pressure is reduced to 75.0 KPa.

What is the new volume?

6.9

1.34

2.56

43.0

2.88

+1
Answers (2)
  1. 23 February, 03:06
    0
    It would be 43.0

    hope it's right sir
  2. 23 February, 03:13
    0
    Answer: The answer is 2.88 m3

    Explanation: Since temperature, pressure and volume are given in the question, the general gas equation will be useful in calculating the new volume.

    General gas equation,

    (P1V1) / T1 = (P2V2) / T2 ... (1)

    Where,

    P1 = Initial pressure

    P2 = Final pressure

    V1 = Initial volume

    V2 = Final volume

    T1 = Initial temperature in kelvin

    T2 = Final temperature in Kelvin

    Hence, from the question:

    P1 = 105 KPa = 105,000 Pa

    P2 = 75 KPa = 75,000 Pa

    V1 = 2.20 m3

    V2 = ?

    T1 = 30 °C = (273+30) K = 303 K

    T2 = 10 °C = (273+10) K = 283 K

    Therefore, substitute these value into the general gas equation as given in eq (1) above.

    V2 = (P1V1T2) / P2V1

    V2 = (105000*2.2*283) / (75000*303)

    V2 = 2.88 m3
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