How many grams of the molecule (C2H4O2) would be required to make 1 L of a 0.5 M solution of the molecule? (Carbon = 12, Oxygen = 16, Hydrogen = 1)

(A) 16

(B) 100

(C) 15

(D) 25

(E) 30

MC₂H₄O₂ = 2 * 12 g/mol + 4 * 1 g/mol + 2 * 16 g/mol = 60 g/mol

c = 0.5 mol/L

V = 1 L

n = c * V

n = 0.5 mol/L * 1 L = 0.5 mol

m = n * M

m = 0.5 mol * 60 g/mol = 30 g/mol

answer E

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