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14 November, 08:30

How many grams of the molecule (C2H4O2) would be required to make 1 L of a 0.5 M solution of the molecule? (Carbon = 12, Oxygen = 16, Hydrogen = 1)

(A) 16

(B) 100

(C) 15

(D) 25

(E) 30

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Answers (1)
  1. 14 November, 08:50
    0
    MC₂H₄O₂ = 2 * 12 g/mol + 4 * 1 g/mol + 2 * 16 g/mol = 60 g/mol

    c = 0.5 mol/L

    V = 1 L

    n = c * V

    n = 0.5 mol/L * 1 L = 0.5 mol

    m = n * M

    m = 0.5 mol * 60 g/mol = 30 g/mol

    answer E

    (-_ - (-_-) - _-)
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